摘要:網(wǎng)絡(luò)工程師是軟考中比較熱門的中級(jí)科目,以下是由希賽網(wǎng)整理的2012年上半年網(wǎng)絡(luò)工程師部分上午真題內(nèi)容。
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網(wǎng)絡(luò)工程師是軟考中比較熱門的中級(jí)科目,以下是由希賽網(wǎng)整理的2012年上半年網(wǎng)絡(luò)工程師部分上午真題內(nèi)容。>>>點(diǎn)擊查看2012年上半年網(wǎng)絡(luò)工程師考試上午真題匯總
● 路由器命令“Router(config)# access-list l deny 192.168.1.1”的含義是__(61)__。
(61)A.不允許源地址為192.168.1.1的分組通過(guò)
B.允許源地址為192.168,1.1的分組通過(guò)
C.不允許目標(biāo)地址為192.168.1.1的分組通過(guò)
D.允許目標(biāo)地址為192.168.1.1的分組通過(guò)
● 局域網(wǎng)沖突時(shí)槽的計(jì)算方法如下。假設(shè)tPHY表示工作站的物理層時(shí)延,C表示光速,S表示網(wǎng)段長(zhǎng)度,tR表示中繼器的時(shí)延,在局域網(wǎng)最大配置的情況下,沖突時(shí)槽等于__(62)__。
(62)A.S/0.7C+2tPHY+8tR
B.2S/0.7C+2tPHY+8tR
C.2S/0.7C+tPHY+8tR
D.2S/0.7C+2tPHY+4tR
● 在局域網(wǎng)標(biāo)準(zhǔn)中,100BASE-T規(guī)定從收發(fā)器到集線器的距離不超過(guò)__(63)__米。
(63)A.100
B.185
C.300
D.1000
● 802.11在MAC層采用了__(64)__協(xié)議。
(64)A.CSMA/CD
B.CSMA/CA
C.DQDB
D.令牌傳遞
● 在無(wú)線局域網(wǎng)中,AP的作用是__(65)__。新標(biāo)準(zhǔn)IEEE802.11n提供的較高數(shù)據(jù)速率可達(dá)到__(66)__。
(65)A.無(wú)線接入
B.用戶認(rèn)證
C.路由選擇
D.業(yè)務(wù)管理
(66)A.54Mb/s
B.100s
C.200Mb/s
D.300Mb/s
● IEEE 802.16工作組提出的無(wú)線接入系統(tǒng)空中接口標(biāo)準(zhǔn)是__(67)__。
(67)A.GPRS
B.UMB
C.LTE
D.WiMAX
● 安全電子郵件使用__(68)__協(xié)議。
(68)A.PGP
B.HTTPS
C.MIME
D.DES
● 建筑物綜合布線系統(tǒng)中的園區(qū)子系統(tǒng)是指__(69)__。
(69)A.由終端到信息插座之間的連線系統(tǒng)
B.樓層接線間到工作區(qū)的線纜系統(tǒng)
C.各樓層設(shè)備之間的互連系統(tǒng)
D.連接各個(gè)建筑物的通信系統(tǒng)
● 下面有關(guān)RMON的論述中,錯(cuò)誤的是__(70)__。
(70)A.RMON的管理信息庫(kù)提供整個(gè)子網(wǎng)的管理信息
B.RMON的管理信息庫(kù)屬于MIB-2的一部分
C.RMON監(jiān)視器可以對(duì)每個(gè)分組進(jìn)行統(tǒng)計(jì)和分析
D.RMON監(jiān)視器不包含MIB-2的功能
● The TCP protocol is a __(71)__ layer protocol. Each connection connects two TCPs that may be just one physical network apart or located on opposite sides ofthe globe. In other words, each connection creates a__(72)__witha length that may be totally different from another path created by another connection. This means that TCP cannot use the same retransmission time for all connections. Selecting afixed retransnussion time for all connections can result in serious consequences. Ifthe retransmission time does not allow enough time for a__(73)__to reach the destination and an acknowledgment to reach the source, it can result in retransmission of segments that are still on the way. Conversely, if the retransnussion time is longer than necessary for a short path, it may result in delay for the application programs.
Even for one single connection, the retransmission time should not be fixed.A connection may be able to send segments and receive__(74)__faster during nontraffic period than during congested periods. TCP uses the dynamic retransmission time,a transmission time is different for each connection and which may be changed during the same connection. Retransmission time can be made__(75)__by basing it on the round-trip time (RTT). Several formulas are used for this purpose。
(71)A.physical
B.network
C.transport
D.a(chǎn)pplication
(72)A.path
B.window
C.response
D.process
(73)A.process
B.segment
C.program
D.user
(74)A.connections
B.requests
C.a(chǎn)cknowledgments
D.datagrams
(75)A.long
B.short
C.fixed
D.dynamic
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